Answer:
The proportion can be used to show that the slope of JL is equal to the slope of MP is [tex]\frac{0-4}{-4-(-7)}[/tex] = [tex]\frac{-4-8}{-1-(-10)}[/tex] ⇒ G
Step-by-step explanation:
The rule of the slope of a line is [tex]m=\frac{y2-y1}{x2-x1}[/tex] , where (x1, y1) and (x2, y2) are two points on the line
∵ The coordinates of the point J are (-7, 4)
∵ The coordinates of the point L are (-4, 0)
∴ x1 = -7 and y1 = 4
∴ x2 = -4 and y2 = 0
→ Substitute them in the rule above to find the slope of LJ
∴ [tex]m_{JL}=\frac{0-4}{-4-(-7)}[/tex]
∵ The coordinates of the point M are (-10, 8)
∵ The coordinates of the point P are (-1, -4)
∴ x1 = -10 and y1 = 8
∴ x2 = -1 and y2 = -4
→ Substitute them in the rule above to find the slope of MP
∴ [tex]m_{MP}=\frac{-4-8}{-1-(-10)}[/tex]
∵ The slope of JL = the slope of MP
∴ [tex]\frac{0-4}{-4-(-7)}[/tex] = [tex]\frac{-4-8}{-1-(-10)}[/tex]
The proportion can be used to show that the slope of JL is equal to the slope of MP is [tex]\frac{0-4}{-4-(-7)}[/tex] = [tex]\frac{-4-8}{-1-(-10)}[/tex]
