Answer:
[tex]\sqrt-{\frac {1}{2} }[/tex]
Step-by-step explanation:
Given expression;
f(x) = 6x² + 3
Unknown:
The zero of the function = ?
Solution:
The zero of the function is the value of x for which the function becomes zero. It is this value that solves the equation;
So;
6x² + 3 = 0
6x² = -3
x² = [tex]-\frac{3}{6}[/tex]
x = [tex]\sqrt-{\frac {1}{2} }[/tex]