Question

Can someone help please

Answer 1

Answer:

a=4

Step-by-step explanation:

Hi there!

We are looking for the value of $a$. We know that $b=11$ and $c=\sqrt{137}$.

We'll start with the Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

Now, we'll subtract $b^{2}$ from both sides so that $a^{2}$ is by itself.

$a^{2} =c^{2} -b^{2}$

We can now substitute our known values of $b$ and $c$ into the equation. Make sure to put the substituted values in parenthesis.

$a^{2} = (\sqrt{137}) ^{2} -(11)^2$

Let's apply the exponents to the values we substituted in:

$a^2=137-121$

$a^2=16$

Now, to eliminate the exponent on $a$, we take the square root of both sides:

$a=\sqrt{16}$

$a=4$

Let me know if you have any questions!