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Answer:
(-0.25, ±√4.6875)
Step-by-step explanation:
The square of the distance from a point on the ellipse to the point (1, 0) is ...
d^2 = (x -1)^2 +y^2
Using the equation of the ellipse to write an expression for y^2, we have ...
d^2 = (x -1)^2 +5 -5x^2
d^2 = -4x^2 -2x +6
The expression on the right is that of a downward-opening parabola with ...
a = -4, b = -2, c = 6
The maximum is located at ...
x = -b/(2a) = -(-2)/(2(-4)) = -1/4
The value of y there is ...
y^2 = 5 -5(-1/4)^2 = 4 11/16
y = √4.6875
The points on the ellipse farthest from (1, 0) are (-0.25, ±√4.6875).
