Answer:
[tex]q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]
Step-by-step explanation:
[tex]6-3q\leq 1\\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-3q-6\le \:1-6\\\\Simplify\\\\-3q\le \:-5\\\\\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\\\left(-3q\right)\left(-1\right)\ge \left(-5\right)\left(-1\right)\\\\Simplify\\\\3q\ge \:5\\\\\mathrm{Divide\:both\:sides\:by\:}3\\\\\frac{3q}{3}\ge \frac{5}{3}\\\\Simplify\\\\q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]