Question

1 poir
A track star in the long jump goes into the jump at 15 m/s and launches
herself at 17.0° above the horizontal.How long is she in the air before
returning to Earth? (g = 9.81 m/s2) (do not include units in answer) *
Helppp now

Answer 1

Her vertical velocity at take off = 15 Sin (17).
V= u + at = (15 Sin (17)) - 9.8 t
9.8 t = (15 Sin (17))
t = (15 Sin (17)) / 9.8
That is the time to get to the highest point.
It takes the same time to return from the highest point back to the ground.