Question

1. find the distance between the points (-4,-6 ) and (8,5) to the nearest 100th of a unit. *
(3 Points)
16.26
16.32
16.28

Answer 1

Answer:

Distance is 16.28.

Step-by-step explanation:

$Distance=\sqrt{((5--6)^{2}+(8--4)^{2} } =\sqrt{11^{2}+12^{2} }=\sqrt{121+144} =\sqrt{265}=16.28$