Question

3. A mercury lamp emits radiation with a wavelength of 4.36 x 10-7 m. Calculate the frequency of this radiation

Answer 1

Answer:

The frequency would be 6.88*10^14Hz

$v=\frac{c}{lambda} = \frac{3.00*10^8 m/s}{4.36*10^-7m}$

We can solve the equation above to get the answer

Answer 2

The frequency of this radiation should be $6.88\times 10^{14}\ Hz.$

Calculation of the frequency

Since  A mercury lamp emits radiation with a wavelength of $4.36 \times 10^{-7}$m

So here the frequency should be

$= c \div \lambda\\\\= 3.00 \times 10^{8} \div 4.36 \times 10^{-7} m.\\\\= 6.88\times 10^{14}\ Hz.$

Hence, we can conclude that The frequency of this radiation should be $6.88\times 10^{14}\ Hz.$

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