What is the value of x, rounded to one decimal place?

Answer:
x ≈ 5.9
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 2.7² = 6.5²
x² + 7.29 = 42.25 ( subtract 7.29 from both sides )
x² = 34.96 ( take the square root of both sides )
x = [tex]\sqrt{34.96}[/tex] ≈ 5.9 ( to 1 dec. place )