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  • 30-10-2020
  • Mathematics
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[tex]v^{3)[/tex]-[tex]11v^{2}[/tex]+13v-30)÷(v-10)

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ZJSG09112007
ZJSG09112007 ZJSG09112007
  • 02-11-2020

Answer:

[tex]v^2-v+3[/tex]

Step-by-step explanation:

[tex](v^3-11v^2+13v-30)\div (v-10)\\\\\frac{v^3-11v^2+13v-30}{v-10}\\\\Factorize\:\:v^3-11v^2+13v-30\\\\=\frac{\left(v-10\right)\left(v^2-v+3\right)}{v-10}\\\\\mathrm{Cancel\:the\:common\:factor:}\:v-10\\\\=v^2-v+3[/tex]

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