Which is a spectator ion from the following complete ionic equation:

H+(aq) + Br–(aq) + K+(aq) + OH–(aq) → H2O(l) + K+(aq) + Br–(aq)

Respuesta :

K+(aq) and Br-(aq)

Because the reactant also appears on the product side in the same form, it does not go through any chemical reaction and is therefore a spectator ion.

Answer : The spectator ions are, [tex]K^+\text{ and }Br^-[/tex]

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given ionic equation in separated aqueous solution will be,

[tex]H^+(aq)+Br^-(aq)+K^+(aq)+OH^-(aq)\rightarrow H_2O(l)+K^+(aq)+Br^-(aq)[/tex]

In this equation, [tex]K^+\text{ and }Br^-[/tex] are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]H^+(aq)+OH^-(aq)\rightarrow H_2O(l)[/tex]

Hence, the spectator ions are, [tex]K^+\text{ and }Br^-[/tex]

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