Question

The sum of 3 consecutive even integers is 36. What is the first of the 3
integers? HURRY I NeED HELP I’ll give brainliest

Answer 1

Given that the sum of 3 consecutive even integers is 36, we can define the variables to be:

• N, (N + 2), (N + 4)

And we can set up the equation as:

$\sf {N + (N + 2) + (N + 4) = 36} \\ \sf{\longrightarrow 3N + 6 = 36} \\ \sf{\longrightarrow 3N = 30} \\ \sf{\longrightarrow N = 10}$

The first even number which we assumed was N, which is equal to 10.

And hence the answer will be

$\leadsto \underline{\boxed{\sf{\pink{\quad10\quad}}}}$

Verification:

3 consecutive even no.s :

• N = 10
• N + 2 = 12
• N + 4 = 14

Their sum = 10 + 12 + 14 = 36

Hence, N = 10 is the solution of the question.