Answer:
-62.02πrads/sec^2
Explanation:
A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.
We need to convert to SI unit
9.549rev/ min= 1rad/sec
Then to convert angular speed of 3,550 rev/min to rad/sec
( 1 rad/sec)/9.549rev/min = x/5600rev/min
Then
(3,550 rev/min)/(9.549rev/min)= 371.77rad/sec
=118.4πrad/sec
6.823rad= 1rev
52.0 revolutions = 52×6.823= 354.796rads
= 113πrads
We will use expresion below to calculate our angular acceleration
w^2 - w^2(0)= 2α¢
Where w= angular speed
w(0)= initial angular
If final angular speed= 0
α=-w^2(0)/2¢
α=(-118.4π)^2/(2×113)
=-14018.56/226
-62.02πrads/sec^2
