Given:
Php 50.00 is paid for the first 10 kilometers and the addition of Php 5.00 for every succeeding kilometer.
To find:
The total fare (F) for x kilometers.
Solution:
Let x be the number of kilometers and F(x) is total fare.
Number of kilometers cannot be negative. So, x is always greater than 0.
Php 50.00 is paid for the first 10 kilometers.
[tex]f(x)=50.00[/tex] for [tex]0\leq x\leq 10[/tex]
The addition of Php 5.00 for every succeeding kilometer.
[tex]f(x)=50.00+5.00(x-10)[/tex] for [tex]x\geq 10[/tex]
Therefore, the required function is
[tex]\begin{cases}50.00, & \text{ if } 0\leq x\leq 10\\ 50.00+5.00(x-10), & \text{ if } x\geq 10 \end{cases}[/tex].