Answer:
The amount invested on 5.6% interest = $80488
The amount invested on 9.7% interest = $69512
Step-by-step explanation:
Given that total amount of investment = $150,000
Let the amount invested on 5.6% interest = $[tex]x[/tex]
Now, amount invested on 9.7% interest = $(150000-[tex]x[/tex])
Total interest to be earned = 7.5%
Formula to be used:
[tex]Simple\ Interest = \dfrac{P\times r\times t}{100}[/tex]
Where, [tex]P[/tex] is the amount invested
[tex]r[/tex] is the rate of interest
[tex]t[/tex] is the time for which amount is invested.
As per question statement:
[tex]\dfrac{x\times 5.6}{100}+\dfrac{(150000-x)\times 9.7}{100}=\dfrac{150000\times 7.5}{100}\\\Rightarrow 5.6x-9.7x=150000(7.5-9.7)\\\Rightarrow 4.1x=150000\times 2.2\\\Rightarrow x = \dfrac{330000}{4.1}\\\Rightarrow x \approx \bold{\$80488}[/tex]
The amount invested on 5.6% interest = $80488
The amount invested on 9.7% interest = $150000 - $80488 = $69512