Question

Suppose a disk drive has the following characteristics: Six surfaces 16,383 tracks per surface 63 sectors per track 512 bytes/sector Track-to-track seek time of 8.5ms Rotational speed of 7,200rpm a) What is the capacity of the drive

Answer 1

Answer:

The answer is "2.95 GB"

Explanation:

Given value:

Surfaces = 6

The tracks per surface =16,383

The sectors per track = 63

bytes/sector = 512

Track-to-track seek time = 8.5ms

The Rotational speed = 7,200rpm

$\text{Drive capacity= surface} \times \text{tracks per surface} \times \text{sectors per track} \times \frac{bytes}{sector}$

                      $= 6 \times 16383 \times 63 \times 512 \\\\= 3170700288 \ B\\\\ = 3023.81543 \ MB \\\\= 2.95294 \ GB$

The drive capacity is 2.95 GB