Answer:
container A is losing water faster
Step-by-step explanation:
Given;
the rate of water loss in container A = 2/3 a gallon every 1/4 an hour
the rate of water loss in container B = 3/4 a gallon every 1/3 an hour
Determine the rate of water loss for each container;
Container A:
Volume of water loss, V = 2/3 a gallon
time of water loss, t = 1/4 an hour = 15 minutes
rate of water loss, Q = V/t
[tex]Q = (\frac{2 }{3}\ gallon) *(\frac{1}{15 \ mins} )\\\\Q = \frac{2}{45}(\frac{gallon}{mins}) = 0.0444 \ gpm[/tex]
Container B:
Volume of water loss, V = 3/4 a gallon
time of water loss, t = 1/3 an hour = 20 minutes
rate of water loss, Q = V/t
[tex]Q = (\frac{3}{4} \ gallon)*(\frac{1}{20 \ mins})\\\\Q = \frac{3}{80} (\frac{gallon}{mins}) = 0.0375 \ gpm[/tex]
The rate of container A is higher than container B, thus container A is losing water faster