Three times the square of a number is greater than a second number. The square of the second number increased by 6 is greater than the first number. Which system of inequalities represents these criteria?

Respuesta :

Given:

Three times the square of a number is greater than a second number.

The square of the second number increased by 6 is greater than the first number.

To find:

The system of inequalities represents these criteria.

Solution:

Let the first number be x and the second number be y.

Three times the square of a number is greater than a second number.

[tex]3\times x^2>y[/tex]

[tex]3x^2>y[/tex]           ...(i)

The square of the second number increased by 6 is greater than the first number.

[tex]y^2+6>x[/tex]       ...(ii)

Therefore, the system of inequalities represents these criteria has inequalities [tex]3x^2>y[/tex] and [tex]y^2+6>x[/tex], where x is first number and y is second number.

The system of inequalities represents given criteria are [tex]3x^{2} > y[/tex] and [tex]y^{2} +6 > x[/tex].

Let us take the numbers as x and y respectively.

First number = x

Second number = y

What is inequality?

Inequality is the relationship between two expressions that are not equal to one another.

Three times the square of the first number is greater than a second number:

This means, [tex]3x^{2} > y[/tex]

The square of the second number increased by 6 is greater than the first number:

This means, [tex]y^{2} +6 > x[/tex]

Therefore, the system of inequalities represents given criteria are [tex]3x^{2} > y[/tex] and [tex]y^{2} +6 > x[/tex].

To get more about inequalities visit:

https://brainly.com/question/11613554

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Universidad de Mexico