Respuesta :
Given:
Three times the square of a number is greater than a second number.
The square of the second number increased by 6 is greater than the first number.
To find:
The system of inequalities represents these criteria.
Solution:
Let the first number be x and the second number be y.
Three times the square of a number is greater than a second number.
[tex]3\times x^2>y[/tex]
[tex]3x^2>y[/tex] ...(i)
The square of the second number increased by 6 is greater than the first number.
[tex]y^2+6>x[/tex] ...(ii)
Therefore, the system of inequalities represents these criteria has inequalities [tex]3x^2>y[/tex] and [tex]y^2+6>x[/tex], where x is first number and y is second number.
The system of inequalities represents given criteria are [tex]3x^{2} > y[/tex] and [tex]y^{2} +6 > x[/tex].
Let us take the numbers as x and y respectively.
First number = x
Second number = y
What is inequality?
Inequality is the relationship between two expressions that are not equal to one another.
Three times the square of the first number is greater than a second number:
This means, [tex]3x^{2} > y[/tex]
The square of the second number increased by 6 is greater than the first number:
This means, [tex]y^{2} +6 > x[/tex]
Therefore, the system of inequalities represents given criteria are [tex]3x^{2} > y[/tex] and [tex]y^{2} +6 > x[/tex].
To get more about inequalities visit:
https://brainly.com/question/11613554