Question

A sample has a nitrate concentration of 4.39 mg/L (4.39 ppm nitrate). Calculate its molar concentration (in moles/L). (This primarily involves unit conversions).

Answer 1

Answer:

$0.0000708\ \text{mol/L}$

Explanation:

The nitrate concentration of the sample = $4.39\ \text{mg/L}=4.39\times 10^{-3}\ \text{g/L}$

Molar mass of $NO^-_3=62.0049\ \text{g/mol}$

The molar concentration is obtained when we divide the concentration by its molar mass in the approriate units.

$\dfrac{4.39\times 10^{-3}}{62.0049}=0.0000708\ \text{mol/L}$

The molar concentration is $0.0000708\ \text{mol/L}$