Question

Veronica is ordering trophies for her school. Company P charges $3.50 for each trophy and a one-time engraving fee of $25. Company R charges $7.50 for each trophy and a one-time engraving fee of $17. Which inequality can be used to find x, the minimum number of trophies that can be ordered so that the total charge at Company P is less than the total charge at Company R?

Answer 1

Answer: Required inequality : $3.50x+25<7.50x+17$

Solution: x<2.

Step-by-step explanation:

Let x = number of trophies.

Company P charges $3.50 for each trophy and a one-time engraving fee of $25.

Total charge for x trophies from Company P=$3.50x+25$

Company R charges $7.50 for each trophy and a one-time engraving fee of $17.

Total charge for x trophies from Company R =$7.50x+17$

When total charge at Company P is less than the total charge at Company R, then

$3.50x+25<7.50x+17\\\\\Rightarrow\ 7.5x-3.5x<25-17\\\\\Rightarrow\ 4x<8\\\\\Rightarrow\ x<2$

Required inequality : $3.50x+25<7.50x+17$

Solution: x<2.

Answer 2

Answer:

<2

Step-by-step explanation: