Question

the sum of 2 numbers is 21 the second number is six times the first

Answer 1

Answer:

$\huge\boxed{\text{Numbers: 3, 18}}$

Step-by-step explanation:

We can create two equations and solve the system of equations to find both the numbers. Let's represent the numbers as a and b.

We can create two equations:

$a+b=21$

$b=6a$

We can now substitute the value of b (6a) into the first equation.

$a + (6a) = 21$

Combine like terms:

$7a=21$

Divide both sides by 7:

$a=3$

Now we know the first number is 3. We can plug this value into one of the equations to find b. Let's plug it into $b=6a$.

$b = 6 \cdot 3\\\\b = 18$

So our numbers are 3 and 18.

Hope this helped!

Answer 2

Step-by-step explanation:

We can create two equations and solve the system of equations to find both the numbers. Let's represent the numbers as a and b.

We can create two equations:

a+b=21a+b=21

b=6ab=6a

We can now substitute the value of b (6a) into the first equation.

a + (6a) = 21a+(6a)=21

Combine like terms:

7a=217a=21

Divide both sides by 7:

a=3a=3

Now we know the first number is 3. We can plug this value into one of the equations to find b. Let's plug it into b=6ab=6a .

b=6⋅3

b=18

So our numbers are 3 and 18.

Hope this helped!