Answer:
The value of the charge is 6 c. Option c.
Explanation:
Electric Field
The electric field is defined as the force per unit charge that would experience a small positive test charge if held at some point in space.
The force F on a charge q at any point in space is equal to the product of the charge and the electric field E at that point
.
[tex]F=q\cdot E[/tex]
Since we know the value of the electric field E=6\ N/c and the force F=36 N experienced by a certain charge q, we can solve the above equation for q:
[tex]\displaystyle q=\frac{F}{E}[/tex]
[tex]\displaystyle q=\frac{36\ N}{6\ N/c}[/tex]
q=6 c
The value of the charge is 6 c. Option c.
