Find the zero of the function f(x)=4x^2-12x+9

Answer:
x = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
Given
f(x) = 4x² - 12x + 9
To obtain the zero let f(x) = 0 , that is
4x² - 12x + 9 = 0 ← in standard form
(2x - 3)² = 0 ← in factored form , then
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = [tex]\frac{3}{2}[/tex]