Question

2. Tyler is solving this system of equations:
4p + 2g = 62
8p - q = 59

He can think of two ways to eliminate a variable and solve the system:

o Multiply 4p + 2g = 62 by 2, then subtract 8p - q= 59 from the result.

• Multiply 8p-q=59 by 2, then add the result to 4p + 2q = 62.

Do both strategies work for solving the system? Explain or show your reasoning.

please help out ://

Answer 1

Answer:

Both of them work

Step-by-step explanation:

by multiplying the first equation by 2 it creates the same coefficient in front of "p" for both equations. same for the second equation and "q".

Answer 2

Both strategies works since we can easily eliminate a variable from both equations.

Given the simultaneous equation solved by Tyler

4p + 2q = 62

8p - q = 59

In order for him to eliminate a variable to solve the system of equations, he must ensure that the coeffiecient of the variable to be eliminated are equations in both expressions. To do that;

• Multiply 4p + 2g = 62 by 2, then subtract 8p - q= 59 from the result. This will give;

8p + 4g = 124

8p - q = 59

Subtract

4q + q = 124 + 59

5q = 183

The second required strategy is  to Multiply 8p-q=59 by 2, then add the result to 4p + 2q = 62, to have:

16p-2q=118

4p + 2q = 62

Adding up

16p + 4p = 118 + 62

20p = 180

p = 9

We can see that both strategies works since we can easily eliminate a variable from both equations.

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