Let event A = The student plays basketball.
Let event B = The student plays soccer.
What is P(AB)?

P(A|B) = 1/3
"A Venn diagram in mathematics is a diagram that uses overlapping circles or other shapes to represent the logical relationships between two or more sets of items. "
"For any experiment, a probability denotes the possibility of outcome for any event."
For event A, the probability of event A is,
P(A) = number of favorable outcomes/ total umber of outcomes
"Conditional probability is the probability of an event occurring given that another event has already occurred."
P(A|B) = P(A∩B)÷P(B)
For given diagram:
Let A represents a set of students playing Basketball and B represents a set of students playing Soccer
So, A = {Fran, Ian, Juan, Ella}
⇒ n(A) = 4
B = {Mickey, Marcus, Ella}
⇒ n(B) = 3
(A ∩ B) = {Ella}
⇒ n(A ∩ B) = 1
sample space: S = {Fran, Ian, Juan, Ella, Mickey, Marcus, Mai, Karl, Jada, Gabby}
⇒ n(S) = 10
Now, we calculate probability of B and A∩B.
P(B) = n(B)/n(S)
⇒ P(B) = 3/10
Also, P(A∩B) = n(A∩B) / n(S)
⇒ P(A∩B) = 1/10
So, the required probability would be,
⇒ P(A|B) = P(A∩B) ÷ P(B)
⇒ P(A|B) = (1/10) ÷ (3/10)
⇒ P(A|B) = 1/3
Therefore, P(A|B) = 1/3
Learn more about probability here:
https://brainly.com/question/12478394
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