Question

A cheetah accelerates at a rate of 6.9 m/s2. After 1.4s it is traveling at 35.7 m/s, what was the initial velocity?

Answer 1

Answer:

-26.04 m/s

Explanation:

a=6.9m/s2, t=1/4s, vf=35.7m/s, vi=?

$v_{f} =v_{i} +at$

$v_{i} =-v_{f} +at=(-35.7m/s)+(6.9m/s^2)(1.4s)=-26.04m/s$

this is a dumb question because that means the cheetah slowed down the sped up at the same rate. :bruh: