Question

secx- cosx = sinx tanx

Answer 1

Answer:

See Explanation

Step-by-step explanation:

$\sec \: x - cos \: x = \sin \: x \tan \: x \\ \\ LHS = \sec \: x - cos \: x \\ \\ = \frac{1}{ \cos x} - cos \: x \\ \\ = \frac{1 - { \cos x}^{2} }{ \cos x} \\ \\ = \frac{ { \sin x}^{2} }{ \cos x} \\ \\ = \frac{ \sin \: x \times \sin x}{ \cos x} \\ \\ = \sin x \: tan x \\ \\ = RHS \\ \\ thus \: proved$