Question

The pressure of a 400 mL sample of KNO₂(g) at constant temperature is increased from 120 kPa to 60 kPa. What is the new volume of the gas?]

Answer 1

Answer:

The answer is 800 mL

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2}$

We have

$V_2 = \frac{120000 \times 400}{60000} = \frac{48000000}{60000} = \frac{4800}{6}$

We have the final answer as

800 mL

Hope this helps you