Question

solve for x in terms of n
please help
will give brainliest answer

Answer 1

Answer:

$x=\sqrt{n-1}$

Step-by-step explanation:

$1^{2} +x^{2} =\sqrt{n} ^{2}$ solve for x & a square root squared cancels out

$x^{2} =n-1$

$x=\sqrt{n-1}$