Question

a line has the points (-3,-8) and (3,y). The slope of the line is 2/3. what is the value of y?

Answer 1

Answer:  The value of y is -4.

Step-by-step explanation:

Using the Slope-intercept form formula, we can use the given coordinates for x and y and input it into the formula to solve for the y intercept.  

Slope Intercept formula:  y = mx + b  where m is the slope and b is the y-intercept.

(-3,-8)  Using this point, we will input the values for x and y.

-8 = 2/3(-3) + b

-8 = -2 + b

+2    +2

b = -6  

The y intercept is -6  and the equation will be y= 2/3x -6

Now input the value for x from the point (3,y)and solve for y.

y = 2/3(3)-6

y = 2 -6

y = -4  

This means that when x is 3, the value of y will be -4.

Answer 2

Answer:

Step-by-step explanation: So given that the slope is and we know that the slope intercept form is where b is a constant in which we are looking for I can use the first point to solve for it then apply the same method to find what y is for the point (3,y).

Step 1 plug in variable

$y=mx+b$  note we use the point (-3,-8)

$-8=2/3*(-3)+b$

Step 2 solve

$-8 = -6/3+b$

$-8=-2+b$

$-8+2=b$

$-6=b$

So the y-intercept for the point (-3,-8) is -6 and we rewrite the formula as

$y=2/3x-6$

Then when we solve for the point (3,y) doing the same thing as we did for the point(-3,-8) to find the y-intercept.

$y=2/3x+b$

$y=2/3*(3)$

$y=2$