Question

balanced equation for the reaction between solid chromium(III) oxide and solid carbon to produce solid chromium and carbon dioxide gas.

Answer 1

Answer:

$2Cr_2O_3(s)+3C(s)\rightarrow 3CO_2(g)+4(s)$

Explanation:

Hello.

In this case, since chromium (III) oxide and solid carbon are respectively Cr₂O₃ and C, the corresponding chemical reaction to yield solid chromium and oxygen is:

$Cr_2O_3(s)+C(s)\rightarrow CO_2(g)+Cr(s)$

However, since two chromium atoms are present at the reactants yet one at the products and three oxygen atoms at the reactants and two at the products, we need to balance it as follows:

$2Cr_2O_3(s)+3C(s)\rightarrow 3CO_2(g)+4(s)$

Best regards!

Answer 2

To balance a reaction means to make the number of atoms the same on both the reactants and products side.

The balanced reaction involved in the reaction is:-

$2Cr_{2}O_{3} \ + 3C -----> 3Co_{2}\ + 4Cr$

The steps for balancing the equation is as follows:-

• Identify each element found in the equation. The number of atoms of each type of atom must be the same on each side of the equation once it has been balanced.
• The net charge must be the same on each side of the equation once it has been balanced.
• If possible, start with an element found in one compound on each side of the equation. Change the coefficients (the numbers in front of the compound or molecule) so that the number of atoms of the element is the same on each side of the equation.
• Once you have balanced one element, do the same thing with another element. Proceed until all elements have been balanced. It's easiest to leave elements found in pure form for last.
• Check your work to make certain the charge on both sides of the equation is also balanced.

By following these steps, you can balance the reaction.

For more information, refer to the link:-

https://brainly.com/question/12271256