Using the graph below, which of the following equations represents the line that is parallel to line FG and passes through the (8, - 3) point?

Answer:
[tex] y = -\frac{7}{4}x + b [/tex]
Explanation:
The equation if the line that is parallel to line FG, will have the same slope as line FG.
To find that equation in slope-intercept intercept form, y = mx + b, we need to find m (slope) and b (y-intercept).
The slope, m, will be the same as the slope of line FG.
Let's calculate the slope of line FG:
F(-4, -2) and G(-8, 5)
[tex] m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 -(-2)}{-8 -(-4)} = \frac{7}{-4} [/tex]
The slope, m, of the line that is parallel to line FG will be -⁷/4.
Substitute x = 8, y = -3, m = -⁷/4 into y = mx + b and solve for the y-intercept, b, of the equation if the line that is parallel bro line FG.
[tex] -3 = -\frac{7}{4}(8) + b [/tex]
[tex] -3 = -\frac{7}{1}2 + b [/tex]
[tex] -3 = -14 + b [/tex]
Add 14 to both sides
[tex] -3 + 14 = b [/tex]
[tex] 11 = b [/tex]
[tex] b = 11 [/tex]
Substitute m = -⁷/4 and b = 11 into y = mx + b
[tex] y = -\frac{7}{4}x + b [/tex]
Therefore, the equation that represents the line that is parallel to line FG and passes through the (8, - 3) point is [tex] y = -\frac{7}{4}x + b [/tex].