Respuesta :

[tex]y = mx + b\\m = \frac{y_2-y_1}{x_2-x_1} = \frac{0-(-2)}{6-0} = \frac{1}{3} \\-2 = \frac{1}{3}(0) + b\\ b = -2\\y = \frac{1}{3}(x) - 2[/tex]

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