Question

A sprinter reaches a velocity of 2 m/s in just 1 second. At a constant rate of acceleration, how long does it take for her to double this velocity? What is her acceleration during this time period? Show you work and explain your answer.​

Answer 1

Answer:

See the answer below

Explanation:

Acceleration is the ratio of velocity and time. Hence;

Acceleration of the sprinter = 2/1 = 2 m/s2.

When the acceleration is constant and the velocity is double:

acceleration = velocity/time

2 = 4/time,

time = 4/2 = 2 s

Hence, the time it will take for the velocity to double with constant acceleration is 2 s. The sprinter's acceleration during this period would be 2 m/s2.

Answer 2

Acceleration is the change in velocity with time. Hence, the time taken to double velocity is 2 seconds and the constant value of acceleration is 2m/s²

Acceleration is the change in velocity with time ;

• Acceleration = (△velocity) ÷ time

• Velocity = 2m/s ; time = 1 second

Acceleration = (2 ÷ 1) = 2m/s²

Double the value of velocity = 2(2m/s) = 4m/s

At constant acceleration ; Acceleration = 2m/s²

Inputting the Values into the equation :

2 = 4 / time

(2 × time) = 4

Time = 4/2

Time = 2 seconds

Therefore, the time taken to double the velocity is 2 seconds

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