Question

The width of a rectangle is 3 less than twice the length, x. If the perimeter of the rectangle is 43 feet, find the dimensions.

Answer 1

Answer:

Step-by-step explanation:

we're given that

$W = 2X - 3\\P = 43$

the perimeter can be defined as

$P = 2X + 2W \\so\\43 = 2X + 2(2X - 3)\\43 = 2X + 4X - 6\\6X = 49\\X = \frac{49}{6}\\ W = 2X - 3\\W = 2(49/6) - 3\\W = 49/3 - 9/3 = \frac{40}{3}$

The rectangle is

$\frac{49}{6} by \frac{40}{3}$ feet