9514 1404 393
Answer:
- as written: 2(x² +1) = 2·3·67
- as standard-form quadratic: 2(x² -200) = 0
Step-by-step explanation:
A prime factorization of a polynomial is one in which each factor cannot be factored further using integers. Here, we can remove a factor of 2 from each side to get ...
2(x² +1) = 2(201)
The constant 201 can be further factored to primes:
2(x² +1) = (2)(3)(67)
__
If the equation is written in standard form:
2x² -400 = 0
again, a factor of 2 can be removed:
2(x² -200) = 0
If the binomial constant were a perfect square, this could be factored further. It is not, so it can't.
