Question

Given the equation 3x + 4y = 10, select a second equation that would create a system with no solutions.

Answer 1

Answer:

$3x + 4y = -10$

Step-by-step explanation:

Given

Equation:

$3x + 4y = 10$

Options:

$3x + 4y = -10$

$3x - 4y = 10$

$3x + 4y = 10$

$3x - 4y = -10$

Required

Select which option answers the question

Analyzing the options one after the other:

Option 1: $3x + 4y = -10$

Represent the given equation as equation 1 and the option as equation 2;

So, we have:

$3x + 4y = 10$

$3x + 4y = -10$

Subtract equation 2 from 1:

$3x - 3x + 4y - 4y = 10 -(-10)$

$0 + 0 = 10 +10$

$0 = 20$

Since,

$0 \neq 20$

We can conclude that both equations has no solution

Hence:

Option 1 answers the question and there's not need to check for other options