Answer:
53295J
Explanation:
The amount of heat to be added can be calculated using the formula:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass (g)
c = specific heat capacity of water
∆T = change in temperature (°C)
According to the provided information, m = 150g, c = 4.18 J/gºC, final temperature= 100°C, initial temperature= 15°C
Hence, Q = m × c × ∆T
Q = 150 × 4.18 × (100°C - 15°C)
Q = 627 × 85
Q = 53295J
The amount of heat added is 53295J
