Question

An arrow is launched vertically up with an initial velocity of 22 m/s . How long will it take the arrow to reach the highest point of it's flight?

Answer 1

Answer:

The initial vertical velocity is the vertical component of the initial velocity: v0y=v0sinθ0=(30.0m/s)sin45°=21.2m/s.

Explanation:

Answer 2

Time taken by arrow to reach height point is 2.2 seconds

Given:

Initial velocity of arrow = 22 m/s

Find:

Time taken by arrow to reach height point

Computation:

We know that, highest point stands when final velocity is 0 m/s

So,

Final velocity = 0 m/s

Gravitational acceleration = 10 m/s²

So,

v = u + at

0 = 22 + 10(t)

10t = -22

t = -22 / 10

t = -2.2 second

Time taken = 2.2 seconds

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