Respuesta :
Answer:
V1 = 10 L
V2 = x L
T1 = 350 K
T2 = 680 K
And you are looking for the second Volume
the image shows the work and the answer is going to be 19.4 L or just 19 L

Hence, 19.4 L is the new volume of gas when the initial volume of 10L at a temperature of 350K and is then heated to 680K.
What is the ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases.
An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given data:
[tex]V_1[/tex] = 10 L
[tex]V_2[/tex] =?
[tex]T_1[/tex] = 350 K
[tex]T_2[/tex]= 680 K
Now using equation:
[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
[tex]\frac{10 L}{350 K} = \frac{V_2}{680 K}\\[/tex]
[tex]V_2[/tex] = 19.4 L
Hence, 19.4 L is the new volume of gas when the initial volume of 10L at a temperature of 350K and is then heated to 680K.
Learn more about the ideal gas equation here:
https://brainly.com/question/18772359
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