Question

A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?

Answer 1

Answer:

20 m/s

Explanation:

velocity after 2 sec.  

v=40+(−10)t

=40−10∗2=20m/s

Answer 2

We have that for the Question "A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?" it can be said that the balls velocity after 2 seconds

• v=67.44m/s

From the question we are told

A ball is thrown up in the air with an initial velocity of 40m/s what is the balls velocity after 2 seconds?

Generally the Newtons equation for the  Motion  is mathematically given as

$v=u+at\\\\Therefore\\\\v=40+9.8*2.8\\\\v=67.44m/s$

Therefore

the balls velocity after 2 seconds

v=67.44m/s

For more information on this visit

https://brainly.com/question/23379286