Question

a car is driving down a road in the early morning when a deer walks into the road. if the deer was 25 meters away when the driver noticed it and the car was traveling 20m/s, did the car strike the deer?

Answer 1

Answer:

For the car not to strike the deer, the minimum deceleration should be 8 m/s² with a combined instantaneous drivers reaction

Therefore, weather the deer is struck by the car depends on the drivers reaction time and deceleration of the car

Explanation:

The given parameters are;

The distance away from the deer the car was when the driver notices the deer = 25 m

The speed of the car = 20 m/s

Therefore, for the car not to strike the deer, the minimum deceleration of the car should be from 20²/(2 × 25) = 8 m/s² for an instantaneous driver reaction time

For a driver reaction time of 0.5 seconds, we have

Distance moved by car = 0.5 × 20 = 10 meters

Distance of the car from the deer at the start of deceleration = 25 - 10 = 15 meters

Minimum deceleration of the car required = 20²/(2 × 15) = 13.$\bar 3$ m/s²

Answer 2

For the car not to hit the deer, the minimum deceleration should be 8 m/s² with instantaneous driver's reaction.

Car hit the deer will depend on the driver's reaction time and deceleration of the car,

Given here,  

Distance, when driver notice the deer = 25 m  

Speed of the car = 20 m/s

So,  the minimum deceleration

$\bold {= \dfrac {20^2 }{2\times 25} = 8\ m/s^2 }$

Therefore, for the car not to strike the deer, the minimum deceleration of the car should be 8 m/s² with an instantaneous driver reaction time.

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