Question

Aqueous sodium carbonate reacts with aqueous copper(II) chloride to form solid copper(II) carbonate and aqueous sodium chloride. What mass of sodium chloride is produced by 23.9 g of sodium carbonate?

Answer 1

Answer:

Explanation:

Na₂CO₃+ CuCl₂ = CuCO₃ + 2NaCl

106 g ( 1 mole )                      117 g ( 2 moles )

106 gram   of Na₂CO₃   produces   117 grams of NaCl

23.9 gram  of Na₂CO₃   produces   117 x 23.9 / 106  grams  

grams of NaCl produced =  117 x 23.9 / 106  =  26.38  gram .