Answer:
Explanation:
If e be the charge on the electron and v be its drift speed after undergoing voltage drop of 118.8 V
eV = 1/2 m v²
1.6 x 10⁻¹⁹ x 118.8 = 1/2 x 9.1 x 10⁻³¹ v²
v² = 41.775 x 10¹²
v = 6.46 x 10⁶ m /s
drift speed of electron = 6.46 x 10⁶ m /s