Answer:
[tex]option \: c. \to \: 0.333 V \: is \: correct.[/tex]
Explanation:
[tex] \\ given : \\ v = ? \\ t = 0.03s \\ L =5.0 \times 10^{-3} H \\ i = 2.0 A\\ then \: the \: inductance \: \boxed{L} \: i s\: given \: by \: the \: form : \\ \boxed{L} = \frac{vt}{i} \\ vt = Li \\ v = \frac{Li}{t} = \frac{5.0 \times 10^{-3} \times 2}{0.03} \\ \\ v = \frac{1.0\times {10}^{ - 2} }{3.0 \times {10}^{ - 2} } = \frac{1}{3} \\ v = 0.33 \: v[/tex]
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