Question

A mischievous cat sees a flowerpot sitting at rest on a windowsill. If it takes 1.2 s for the flowerpot to fall from the window, how high up was the window?

Answer 1

Given that,

Initial speed of a cat is 0 because it was at rest.

If it takes 1.2 s for the flowerpot to fall from the window, we need to find the height reached by the cat.

Using second equation of motion to find it as follows :

$d=ut+\dfrac{1}{2}at^2$

Put u = 0 and a = g

$d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (1.2)^2\\\\d=7.05\ m$

So, it will move to a height of 7.05 m.