Question

PLEASE HELP ME BOO!! A rocket, initially at rest, steadily gains speed at a rate of 17.0m/s2 for 5.50s during take-off.

Answer 1

Answer:

$v\: is : 93.5 \: m {(s)}^{ - 1}$

Explanation:

$given : \\ acceleration \: \boxed{a} = 17.0 \: m {(s)}^{ - 2} \\ time\: \boxed{t} = 5.50 \: s \\ but \:\: \boxed{a} = \frac{v}{t} \\ v = at = 17 \times 5.5 = 93.5 \\ the \: velocity\: \boxed{v} \: is : 93.5 \: m {(s)}^{ - 1}$

if the velocity is what you require.....cos there was no clear statement of the required value.

♨Rage♨

Answer 2

Answer:

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