Question

‼️NEED HELP ASAP‼️
find f'(x) for f(x) = ln(x^4 + e^2x)

Answer 1

Answer:

We can do this with u substitution

$f(x) = ln(x^4+e^2^x)\\u = x^4+e^2^x\\f(x) = ln(u)\\f'(x) = \frac{u'}{u} \\u' = 4x^3 + 2e^2^x \\f'(x) = \frac{4x^3 + 2e^2^x}{x^4+e^2^x}$

we can't simplify further