Find the value of X, please help me!!

Answer:
[tex]\sqrt{33}[/tex]
Step-by-step explanation:
Use the Pythagorean Theorem For the Triangle with Sides 11, 13, and Height(blue dashed line)
b=height (blue-dashed line)
[tex]11^2+b^2=13^2[/tex]
[tex]169-121=b^2[/tex]
[tex]48=b^2[/tex]
[tex]\sqrt{48} =b[/tex]
Use the Pythagorean Theorem Again for sides 9, x, and height which is [tex]\sqrt{48}[/tex]
[tex]x^2+\sqrt{48}^2=9^2[/tex]
([tex]\sqrt{48}^{2}[/tex] is [tex]48[/tex]
[tex]81-48=x^2[/tex]
[tex]33=x^2[/tex]
[tex]x=\sqrt{33}[/tex]
Hope it Helps!