Answer:
(6, 10)
Step-by-step explanation:
Vertex form of an equation of a quadratic function is y=a(x-h)²+k, where vertex is (h, k)
We can find h and k by comleting the square:
[tex]y=x^2-12x+46\\\\y=x^2-2\cdot x\cdot\underline6+6^2-6^2+46\\\\y=\underline{x^2-12x+6^2}-36+46\\\\y=(x-6)^2+10\quad\implies\quad h=6\,,\ \,k=10\,,\ \,a=1[/tex]
